DatePart Function

Syntax

DatePart(interval, dateexpr)

Group

Time/Date

Description

Return the number from the date corresponding to the interval.

Parameter Description
interval This string value indicates which kind of interval to extract.
dateexpr Get the interval from this date value. If this value is Null then Null is returned.
Parameter Description
yyyy Year (100-9999) Quarter (1-4)
m Month (1-12)
y Day of year (1-366)
d Day (1-31)
w Weekday (1-7)
ww Week (1-53)
h Hour (0-23)
n Minute (0-59)
s Second (0-59)

See Also: DateAdd, DateDiff.

Example

Sub Main
Debug
.Print DatePart("yyyy",#1/1/2000#) ' 2000
End
Sub